3x^2/(4x)=6,81

Solution for 3x^2/(4x)=6,81 equation:

3x^2/(4x)=6.81

We move all terms to the left:

3x^2/(4x)-(6.81)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

3x^2/4x-6.81=0

We multiply all the terms by the denominator


3x^2-(6.81)*4x=0

We multiply parentheses

3x^2-27.24x=0

a = 3; b = -27.24; c = 0;
Δ = b2-4ac
Δ = -27.242-4·3·0
Δ = 742.0176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27.24)-\sqrt{742.0176}}{2*3}=\frac{27.24-\sqrt{742.0176}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27.24)+\sqrt{742.0176}}{2*3}=\frac{27.24+\sqrt{742.0176}}{6}
$